whats the final answer to: y+7=−7(x+1) Should be an equation for a tangent line*
You know the equation for a tangent line, meaning you know how to find derivatives, but you're struggling with basic algebra?
I got the results but for some reason its not matching up exactly with the possible answers.
You're getting \(y=-7x-14\)?
which is why i want someone to give me the answer so i can be sure i didn't make a mistake earlier in the problem.
yea.
What is f(x)?
f(x) = -4x + 3/x at x = -1
Yeah, I can tell already it's at the point (-1, -7) based on the form of your tangent line.
Okay, so I'm getting: \[ f'(x) = -4 + -\frac{3}{x^2}\implies f'(-1) = -4-3 = -7 \]So that part is correct.
yea
You are fine so far.
ok so what should i do next?
What is the question?
Write an equation for the tangent line to f(x) = -4x + 3/x at x=-1
Oh wait, we need to find out \(\large f(-1)=-4(-1)+\frac{3}{-1}\)
possible answers : A) -7x + y = -6 B) -6x + 2y = -5 C) 7x + y = -6 D) 6x + 2y = -5
oh
4-3 = 1.... there was your problem.
\[y-1=-7(x+1)\]
Thank you for the help!
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