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Mathematics 21 Online
OpenStudy (anonymous):

How do you factor 5ab-2b squared-2b+5a?

OpenStudy (lgbasallote):

try rearranging them \[\implies 5ab + 5a - 2b^2 - 2b\] do you see how to factor it now? or no?

OpenStudy (anonymous):

No... Like I want to be taught the process to fully factor it

OpenStudy (lgbasallote):

well the first step is to rearrange it (like i did)

OpenStudy (lgbasallote):

the next step...is to group the terms like this \[\implies (5ab + 5a) + (-2b^2 - 2b)\] still don't see the factor?

OpenStudy (anonymous):

Yeah I see it .. So when you rearrange it... you do it according to the numbers and letters right?

OpenStudy (lgbasallote):

yes

OpenStudy (lgbasallote):

because you want the common terms to be together

OpenStudy (anonymous):

Oh okay, so for instance, if it said 6ab+6a, I would group that first? Does it matter which order it's in?

OpenStudy (lgbasallote):

it depends... remember: in addition there is a commutative property...that means order doesn't matter... but in subtraction...there's no commutative property

OpenStudy (lgbasallote):

unless you do it like this 6ab - 6a => -6a + 6ab that's fine.. but these are not equal 6ab - 6a => 6a - 6ab

OpenStudy (anonymous):

Oh okay, so what would you do if it was in subtraction? Can you give me another question to solve to see if I understand?

OpenStudy (lgbasallote):

sure try this \[\huge 5xy + 10y - 4x^2 + 8y^2\]

OpenStudy (lgbasallote):

it's a bit different since you don't have same numbers here

OpenStudy (lgbasallote):

sorry...i have to go now...

OpenStudy (anonymous):

Okay

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