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Chemistry 18 Online
OpenStudy (anonymous):

If 0.765g of an unknown gas were collected at 741 torr and 95C in a 245 mL container, then what is the molecular weight of this unknown gas?

OpenStudy (anonymous):

Using PV=nRT, I have (741 torr)(.245Liter)=(.765/x)(R)(368 Kelvin) Not sure what R is...

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