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OpenStudy (anonymous):
If 0.765g of an unknown gas were collected at 741 torr and 95C in a 245 mL container, then what is the molecular weight of this unknown gas?
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OpenStudy (anonymous):
Using PV=nRT, I have (741 torr)(.245Liter)=(.765/x)(R)(368 Kelvin) Not sure what R is...
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