When simplified, (1+1/x)/{(1/x^2)-1} equals?
1/x^3 +1/x^2 -1/x -1
\[\frac{ 1+\frac{ 1 }{ x } }{ \frac{ 1 }{ x^2 }-1 }\]
I would make the numerator and denominator into 1 fraction. This is the same as in basic math. find a common denominator and add
This one is multiple choice. The answers are between a) x/1-x b) x/x-1 c) 1/x-1 d) x-1/x
\[\frac{ \frac{ x }{ x } +\frac{ 1 }{ x }}{ \frac{ 1 }{ x^2 } -\frac{ x^2 }{ x^2 }}=\frac{ \frac{ x+1 }{ x } }{ \frac{ 1-x^2 }{ x^2 } }\]
Now just like in basic math when we divide fractions we can flip the denominator and multiply instead
\[\frac{ x+1 }{ x }\times \frac{ x^2 }{ 1-x^2 }=\frac{ (x+1)x }{ 1-x^2 }\]You can see that an x will cancel from the bottom.
we can factor the denominator next
Do you want to learn how to do it or just have the answer? Think wisely before you answer this question
Sure, could you teach me
\[\frac{ (x+1)x }{ 1-x^2 }=\frac{ (x+1)x }{ (1-x)(1+x) }=\frac{ x }{ 1-x }\]
just write down each of my posted steps and ask me any questions you don't understand. I have posted all of my work and I tried to post my thought process as well.
After studying it a bit, I understand it. Thank you very much.
yw
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