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Mathematics 11 Online
OpenStudy (anonymous):

Add: (x+20)/(x^2-16)+3/(4-x)

OpenStudy (kropot72):

You need to find a common denominator for the addition. The first step is to factorise x^2-16. Can you do that?

OpenStudy (anonymous):

meaning I would need to multiply (4-x) by (-x-4)?

OpenStudy (anonymous):

or divide by (-x-4)?

OpenStudy (kropot72):

You first factors will do nicely! So we get: \[\frac{x+20}{(x-4)(-x-4)}+\frac{3}{4-x}\]\ So you can see that the denominator of the first term can be the common denominator for the addition. Can you do the rest now?

OpenStudy (anonymous):

Okay so the numerator would be (x+23), right?

OpenStudy (kropot72):

No. The numerator will be x + 20 -3(-x - 4)

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