Question

the dimension of a rectangle are such that its length is 5 in. more than its width.if the length were doubled and if the width were decreased by 2 in., the area would be increased by 70 in^2 what are the lenghts and widths of the rectangle?

Answer 1

width =x
length = (x+5 )
Area 1=x(x+5)
New rectangele
Length doubled = 2(x+5)
width decrease = x-2
New area is 70 more then the other rectangle so
Area 1 + 70 = 2(x+5)(x-2)
x(x+5) +70 = 2(x+5)(x-2)
now solve this and find x

Answer 2

i got 20.66666667

Answer 3

hmm did you got 2 values of x?