Question

A possible interval of values of k for which the equation (x+k)x=-4,have two real solutions is :

Answer 1

k>0,k>2,k>4,k<4

Answer 2

(x+k)x=-4

x^2 + kx + 4 = 0

Answer 3

First, rearrange the equation into the form ax^2 + bx + c = 0 after expanding the original equation.

Answer 4

I got that already @Yahoo!

Answer 5

what next ?

Answer 6

For two real solutions

b^2 - 4ac > 0

Answer 7

x^2 + kx + 4 = 0

k^2 - 16 > 0

Answer 8

k >4 < Answer

Answer 9

yup..)