Ask your own question, for FREE!
Mathematics 14 Online
OpenStudy (anonymous):

In the system shown below, what is the sum of the x-coordinates of all solutions? pic attached

OpenStudy (anonymous):

OpenStudy (raden):

from the 1st equation, 3y^2 - 5x^2 = 7 ----> 3y^2 = 5x^2 + 7 now, subtitute it into the 2nd equation

OpenStudy (anonymous):

k

OpenStudy (raden):

what u get ?

OpenStudy (anonymous):

idk how to do it, ik how to substitute but not this one

OpenStudy (anonymous):

am i solving the second equation u wrote... the one the arrow is pointing too?

OpenStudy (raden):

well, i we substitute the value of 3y^2 = 5x^2 + 7 to 3y^2-x^2=23, gives 5x^2 + 7- x^2=23, right ?

OpenStudy (raden):

*if

OpenStudy (anonymous):

right

OpenStudy (raden):

then, just simplify it, what u get ?

OpenStudy (anonymous):

5x^2 - x^2=16

OpenStudy (anonymous):

or 4x^2=16

OpenStudy (raden):

or 4x^2 - 16 = 0, right ?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

x=-2 and x=2??

OpenStudy (raden):

ok now without to find the roots, we can determine the sum of roots of equation kuadratic : ax^2-bx+c=0, just use formula x1 + x2 = -b/a

OpenStudy (anonymous):

which u get what once there plugged in?

OpenStudy (anonymous):

x1+x2=o/4?

OpenStudy (raden):

ax^2+bx+c=0... (sorry, trouble my keyboard) yes.. 0/4 = 0

OpenStudy (anonymous):

so the sum of all x coordinates is 0?

OpenStudy (raden):

yeps... another way, from ur solution : x1=-2 and x2=2 so, x1+x2 = -2 + 2 = 0

OpenStudy (anonymous):

thankyou

OpenStudy (raden):

welcome

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!