Question

help pleasee?

Answer 1

Part 1: The index on the radicals are the same (2) so we can write that as a single radical.
\[\sqrt{50*(x^{7})*(x^{1})*(y^{7})*(y ^{4})}\]
Then simplify this. What do you get?

Answer 2

50 x^8y^11?:/

Answer 3

I got kicked off.

Answer 4

Correction left out the 6: \[\sqrt{50*6*x^{7}*x ^{1}*y^{7}*y ^{4}}\]

Answer 5

so we have: \[\sqrt{300x ^{8}y ^{11}}\]

Answer 6

So what is the greatest factor of 300 that can be written as a square?

Answer 7

OK, The factor of 300 we are going to choose is 3*100, where 100 = 10^2
Rewrite equation:
\[\sqrt{10^{2}*3*x ^{8}*y}\]

Answer 8

That last term should be y^11

Answer 9

okay, i switched computers, sorry about that!:(

Answer 10

So our index is 2 on our radical.
So we can divide each exponent under the radical by 2:

for 10^2: 2/2 = 10^1
for 3^1 = 1/2 = 3^1/2
for x^8: 8/2 = x^4
for y^11: y^10/2 * y^1/2 = y^5 *y^1/2
So this would simplify to:
\[10x ^{4}y^{5} \sqrt{3y}\]

Answer 11

thank you phil!!! :D it makes more sense now