Question

Check my answers:

List of Axioms:
1. The whole is equal to the sum of its parts
2. If equals are added to equals, the sums are equal
3. Quantities that are equal to the same quantities of equal quantities are equal to each other
4. If equals are subtracted from equals the remainders are equal
5. Doubles of equals are equal

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1. Given: AB = DE, BC = EF
Prove: AC = DF

Answer: Axiom 3

2. Given: AB = AC, DB = EC
Prove AD = AE

Answer: Axiom 3

3. Given: Angle 1, Angle 2, Angle 3
Prove: Angle ABC = Angle 1 + Angle 2 + Angle 3

Answer: Axiom 1

Answer 1

a simple yes or no will do along with the ones that are worng

Answer 2

I think for 1) you have to use multiple steps (and reasons)

you start with givens
AB = DE, BC = EF
you then add
AB+BC = DE +EF
and you can say this is still true because of
2. If equals are added to equals, the sums are equal

then you can combine AB+BC to get AC because
1. The whole is equal to the sum of its parts

same for DE+EF = EF
1. The whole is equal to the sum of its parts

so you get
AC= EF


so it took 3 steps:
Givens
equals added to equals
the whole is equal to the sum of its parts

Answer 3

So 1 is Axiom 1 and the rest are correct?

Answer 4

Is there supposed to be only 1 answer for each?

Answer 5

yes

Answer 6

it's multiple choice on my hw, but once again this is an area that I struggle with in geometry

Answer 7

because I would say the first question needs both axiom 2 and axiom 1

Answer 8

I don't understand the Q 2 or 3. If there is a figure that adds more info, that might help.

I assume for Q3, a figure shows the 3 angles are next to each other, in which case you can add them up to get a "big" angle ABC

Answer 9

Here is the picture for # 1

Answer 10

Picture for # 2