Question

A 50.0 mL sample containing Cd2 and Mn2 was treated with 43.3 mL of 0.0400 M EDTA. Titration of the excess unreacted EDTA required 17.1 mL of 0.0310 M Ca2 . The Cd2 was displaced from EDTA by the addition of an excess of CN–. Titration of the newly freed EDTA required 11.1 mL of 0.0310 M Ca2 . What were the molarities of Cd2 and Mn2 in the original solution?

Answer 1

@levinelevine any idea on this?

Answer 2

@robtobey any idea on this?

Answer 3

@sauravshakya any idea on this?

Answer 4

@UnkleRhaukus Help pleasr

Answer 5

@TuringTest Help please

Answer 6

@Preetha Help Please

Answer 7

its very easy, just follow the dilutions and the reactions until you get the initial concentration.