With the restriction x ≠ 0, Which of the following is the simplified form of
\[\frac{ 6x^{4} }{ 4x^{9} } \times \frac{ 12x^{2} }{ 3x^{5} } = \frac{(6)(12)x^{4}x^{2} }{ (4)(3)x^{9}x^{5} } = \frac{ 72x^{6} }{ 12x^{14} }\]
can that be simplified again?
yes :)
I wanted to post it before I messed up the equation editor stuff ;)
Do you see the idea though? You can also cancel out terms before you multiply everything together... that's another good approach.
would the answer be 6x^2?
The "6" part is correct, but you didn't simplify the x's correctly.
You simplify exponents like: \[\frac{ x^{6} }{ x^{14} } = \frac{ 1 }{ x^{8} }\]
x^8?
yes, but it's in the denominator. 72 / x^8
Is that one of your choices? Another way to write the same thing is to put the variable in the numerator but express the exponent as a negative. Like: 72x^(-8)\[\frac{ 72 }{ x^{8} } = 72x^{-8}\]
oops, that should have been "12" everywhere I wrote "72"
no. the closest to that is 6/x^8
sorry sorry sorry. You're right :) Too much scrolling up and down. That is correct.
thanks!!!
the 72 and 12 reduce to give you the 6, and x^6 / x^14 reduces to 1/x^8 All together, it's 6 / x^8
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