what is the temperature change if 83680 joules of heat are ADDED to 1KG of water?
if i remember correctly 4.2 joules of energy will increase the temperature of 1 gram of water by 1 degree C.
thats alot of math to do lol
Well, what's it for, home ec?
no its for my IPC class or physics or chemistry whatever u wanna call it its for my hw but i skipped school today so i didnt get to finish the lesson on this specific subject so im trying to get help to understand it
ok use this formula H = m * 4.2 * t where H is the heat energy added . m = mass of water in grams, and t = rise in temperature
so my formula would be H=1kg*4.2*83,680J??
no H = 83,680 so its 83,680 = 1000*4.2 * t now solve for t
need any more help?
no i think im good ^__^ thank uuu
yw
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