Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (anonymous):

For the function 32/x+3, find (g^-1∘ g)(5). 11 5 1 2

OpenStudy (anonymous):

what do you think ?

OpenStudy (anonymous):

and by g^-1 you mean inverse of g ?

OpenStudy (anonymous):

I guess , lol . Thats how the question looks.

OpenStudy (anonymous):

ok.. so what do you think is the answer ? in general what is the result of the composition of inverse of a function with the function ?

OpenStudy (anonymous):

I have no idea , I worked it out and got 4 . lol But i guess I didn't work it out right .

OpenStudy (anonymous):

g^-1∘ g is like g^-1(g(x) right ?

OpenStudy (anonymous):

right .

OpenStudy (anonymous):

now when we plug the real function into the inverse of the function we really get back x

OpenStudy (anonymous):

it is because that if we have for example f(x) and we plug into it 5 we get f(5) and for the inverse f^-1(x) when we plug f(5) we get 5

OpenStudy (anonymous):

do you understand what i mean ?

OpenStudy (anonymous):

Kinda. I'm just kinda lost.

OpenStudy (anonymous):

|dw:1353107382159:dw|

OpenStudy (anonymous):

lets do it with an example x^2 plug 5 : f(5) = 25 now lets look for f^-1(x) it is sqrt(x) now plug in there 25 we get sqrt(25) = 5

OpenStudy (anonymous):

this is an example of a general property.. f^-1(f(x)) = x

OpenStudy (anonymous):

oh , i understand a little bit better.

OpenStudy (anonymous):

the real function takes a value from the domain and returns the corresponding value from the range the inverse take a value from the range and returns the corresponding value from the domain

OpenStudy (anonymous):

so if you took x and plug it into f(x) you got f(x) (domain) (range) now you plug f(x) into f^-1(x) and you got x back (range) (domain)

OpenStudy (anonymous):

im feeling like im saying the same thing but i hope it helps

OpenStudy (anonymous):

your not , im understanding. i just have to take a second to think about it. so the answer is 5 ?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Thank you sooo much . ! (:

OpenStudy (anonymous):

youre welcome :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!