Question

how do you solve 3x-6y=6 , 4x-5y=4 using elimination

Answer 1

\[\left(\begin{matrix}3x-6y=6 \\ 4x-5y=4\end{matrix}\right)\] you need to multiply one of the equations by something so that when you add down one of the variables will cancel what do you think?

Answer 2

actually in this case you need to multiply both equations by somthing

Answer 3

when i multiplied both i still didnt get the correct answer :/

Answer 4

what did you multiply by? try 4 on the first equation and -3 on the second

Answer 5

i multiplied five on the first and six on the second. ill try what you said . thank you !!

Answer 6

still didnt work :(

Answer 7

\[4\times(3x-6y=6) \rightarrow12x-18y=24\] and \[-3 \times (4x-5y=4) \rightarrow -12x +15y=-12\]

Answer 8

where did you get z from??

Answer 9

\[\left(\begin{matrix}12x-18y=24 \\ -12x+15y=-12\end{matrix}\right)\]

Answer 10

x=(6+6y)/3 ______________1
4((6+6y)/3)-5y=4
8+8y-5y=4
3y=4-8
3y=-4
y=-4/3 substitute in 1
x=(6+6(-4/3))/3=-2/3

Answer 11

im sorry i meant x

Answer 12

\[-3y=12\] and\[y=-4\]

Answer 13

then plug in -4 to find x

Answer 14

Mr. Me : for x -6 x 4 = -24 how did you get 18 for y in the first equation??

Answer 15

by elimination:y=-4/3,x=-2/3

Answer 16

oopsss!!! its should be 24

Answer 17

sorry

Answer 18

and when its 24 it doesnt work out. im really confused !!!

Answer 19

if its 24 you will end up with -9y=12 and then solve for y and you get y=12/9 which simplifies to y=4/3

Answer 20

y=-4/3

Answer 21

i understand. thank you Mr. Me and ASAAD123 !!

Answer 22

3x=6+6y
x=(6+6y)/3 ______________1
4((6+6y)/3)-5y=4
8+8y-5y=4
3y=4-8
3y=-4
y=-4/3 substitute in equation1
x=(6+6(-4/3))/3=-2/3

Answer 23

^ Thanks !

Answer 24

welcome