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Find all rational zeros of the polynomial P(x)=x^4-3x^3-2x^2-6x-8 Enter the rational zeros in a comma separated list.
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Are you sure this is the exact question and all the signs are correct?
Unfortunately Yes
I think I got it: f(x)=0= x^4-3x^3-2x^2-6x-8 Factor by grouping: (x^4-2x^2-8)-(3x^3-6x) = 0
Missed a sign: x^4-2x^2-8)-(3x^3+6x) = 0
Try to factor this and tell me what you get
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Are you there?
Im here @philo1234
Ok try to factor the last expression by grouping that I gave. and tell me what you got
(x^4-2x^2-8)-(3x^3+6x) = 0
(x+1)(x-4)(x^2+2)
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There it is. good job.
so 1, 4 and sqrt 2 is the answers
\[-1,4, \pm i \sqrt{2}\]
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