Question

A ball is thrown upwards with an initial velocity of 10 m·s−1.

Determine the maximum height reached above the thrower's hand.

Determine the time it takes the ball to reach its maximum height.

Answer 1

Is it thrown vertically upwards?

Answer 2

If yes then,
v^2 =u^2 +2as
0^2 = 10^2 + 2*(-9.81) *s

Answer 3

Solve for s ...
where s= max height reached by the ball.

Answer 4

YA r8.......

Answer 5

To calculate time u can use:
s= (u+v)/2 *t

Answer 6

Or,
v=u+at