Find the equation of a quadratic function f whose graph has a vertical axis of symmetry x = -2, the range of f is given by the interval [4 , +infinity) and f(2) = 8.
you are being told in a round about way that the vertex is \((-2,4)\)
this means it looks like \(y=a(x+2)^2+4\) the only number you do not know is \(a\)
but you can solve for it, since \[f(2)=8\]you know \(8=a(2+2)^2+4\) and so \[16a+4=8\] \[16a=4\] \[a=\frac{1}{2}\]
how come the vertex is (-2,4)? what does the vertical axis of symmetry x= -2 mean?
|dw:1353124009816:dw|
means a) the parabola is symmetric about the line \(x=-2\) and b) the first coordinate of the vertex is \(-2\)
the fact that the range is \([4\infty)\) tells you the second coordinate of the vertex is \(4\)
I see...that's what I don't know before. I just know that there is a line x=-2
|dw:1353124262023:dw| if I may ask more, if the graph's like this, how would you say it in words?
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