Could some clear this up for me please? Its a bit confusing. Find the equation of the line that is perpendicular to 4x + 7y = 13 and passes through point (-2,6). (Hint: put 4x + 7y = 13 into slope intercept FIRST.)" http://i.imgur.com/zooBV.png
What is 4x + 7y = 13 in slope intercept form? Can you do that?
@Guilty404 tell me what you get?
I am. Just trying to figure it out.
Show me your steps.
Well I'm trying to figure out were to start
4x + 7y = 13 We need: y = mx + b right?
So lets move our 4x to other side of the equal sign. This way the problem will at least resemble y=mx+b
4x + 7y = 13 -4x -4x ------------- 7y = -4x + 13
Do you understand that?
Yes combining equal terms?
or like terms
No, I did not combine anything. I just moved a term in this case... "4x" to the other side.
Oh, alright. Well from the equation you posted. I can tell what you're doing.
Upon moving the 4x... I had to subtract .... so that minus sign had to stay with it.
7y = -4x + 13 Remember we want: y = mx+b So we must solve for 'y'
\[\frac{ 7y= -4x+13 }{ 7 }\]How can we solve for y? It is being multiplied by 7... so we must divide both sides entirely by 7.
\[y=\frac{ -4 }{ 7 }x+\frac{ 13 }{ 7 }\]
Now, we must plug this into the point slope form equation.. since they want the equation that is perpendicular BUT also passes through (-2,6).
y-y1=m(x-x1) \[y-6=\frac{ 7 }{ 4 }(x+2)\]
@Guilty404 do you understand everything so far?
I am understanding it so far.
\[y-6=\frac{ 7 }{ 4 }x+\frac{ 7 }{ 2}\]
Now we add 6 to both sides... 6 + 7/2 = 19/2
\[y=\frac{ 7 }{ 4 }x+\frac{ 19 }{ 2 }\]
So by adding 6 to both sides, the 6 was eliminated?
Yes, because it was like doing this... y - 6 = 7x + 3 +6 +6 ------------- y = 7x + 9
@Guilty404 so you understand now?
I do*
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