Question

Use the Rational Root Theorem to list all possible rational roots of the polynomial equation x3 – x2 – x – 3 = 0. Do not find the actual roots. (1 point)
–3, –1, 1, 3
1, 3
–33
no roots

Answer 1

i think it is a am i right yes or no

Answer 2

\[a_n = 1 \quad a_0 = -3\]

Answer 3

\[
\pm \frac{1,3}{1} = 1, 3, -1, -3
\]

Answer 4

you're right, but what matters is the process you used.

Answer 5

ok can u check another one for me

Answer 6

What does Descartes's Rule of Signs tell you about the real roots of the polynomial?

–2x3 + 3x2 – 5x – 2 = 0 (1 point)
There is one positive root and either 2 or 0 negative roots.

There are either 2 or 0 positive roots and there are either 2 or 0 negative roots.
There is one positive root and one negative root.
There are either 2 or 0 positive roots and one negative root.
i think it c

Answer 7

@wio am a right

Answer 8

Well it has 3 roots. We know it has 2 or 0 positive roots.

Answer 9

so its d

Answer 10

you didn't list d

Answer 11

aThere is one positive root and either 2 or 0 negative roots.
bThere are either 2 or 0 positive roots and there are either 2 or 0 negative roots.
cThere is one positive root and one negative root.
dThere are either 2 or 0 positive roots and one negative root.

Answer 12

d looks best.

Answer 13

ok i have 1 more

Answer 14

Find a third-degree polynomial equation with rational coefficients that has roots –4 and 6 + i. (1 point)
x3 – 8x2 – 11x + 148 = 0
x3 – 8x2 – 12x + 37 = 0
x3 – 12x2 + 37x = 0
x3 – 8x2 – 11x = 0

i think this one is b or a

Answer 15

Obviously it is a or b, since 0 is not a root.

Answer 16

so which one do u think it is im going with a

Answer 17

can't you just plug 4 into one of them to find out?

Answer 18

whats number 2 to this ?

Answer 19

a
a
d
a
d