Question

A druggist has two mixtures of a certain chemical and water, one containing 10% of the chemical and the other containing 40% of the chemical. How much of each mixture should he use to make 10 ounces that contain 25% of the chemical?

Answer 1

Really? We just answered this for you.

Answer 2

yes

Answer 3

i need help please

Answer 4

x+y = 10
.1x + .4y = (.25)10

Answer 5

7.5

Answer 6

?? what about 7.5

solve system using substitution
y = 10-x
--> .1x +.4(10-x) = 2.5
...
solve for x

Answer 7

answer is 2.5

Answer 8

no...show your steps so i know what you did wrong

Answer 9

okey 1

Answer 10

@dumbcow my answer is 1

Answer 11

for x?

no, by plugging 1 in you can see that both sides will not equal each other

seems like you are guessing

Answer 12

okey men isx ounces of 10% soln mixed with (10 – x) ounces of 40% soln. as total final volume is 10 ounces
amount of chemical in x ounces = 0.1x
amount of chemical in (10 – x) ounces = 0.4(10 – x) = 4 – 0.4x
amount of chemical in 10 ounces = 10 × 0.25 = 2.5

chemical balance
0.1x + 4 – 0.4x = 2.5
0.3x = 1.5
x = 5 ounces of 10% mixed with
(10 – 5) = 5 ounces of 40% to give 10 ounces of 25%

Answer 13

yes solution is (5,5)

how do you go from guessing to writing a well laid out solution ...haha