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Mathematics 15 Online
OpenStudy (anonymous):

Hey! Can someone please help me with B, C, and D? Thanks a lot! :) P.S. check the attachment! :P

OpenStudy (anonymous):

OpenStudy (anonymous):

for b, make the csc into 1/sin

OpenStudy (anonymous):

i did but how would you solve it?

OpenStudy (anonymous):

you will get sin^2(x) = 3/4

OpenStudy (anonymous):

would you leave it like that?

OpenStudy (anonymous):

nope. square root and use sin inverse

OpenStudy (anonymous):

would i put it into the calculator?

OpenStudy (anonymous):

remember square root gives you 2 solutions, use sin inverse for both

OpenStudy (anonymous):

\[\sin^{-1} (\sqrt{\frac{ 3 }{ 4 }}) and \sin^{-1} (-\sqrt{\frac{ 3 }{ 4 }})\]

OpenStudy (anonymous):

would i put that into the calc?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

is there a way i could do it w/o the calc?

OpenStudy (anonymous):

it is a special angle. you must memorize it

OpenStudy (anonymous):

the answer is pi/3

OpenStudy (anonymous):

how did you get that?

OpenStudy (anonymous):

you must memorize the special angles. or you can play around with the calculator and see what you get tin degrees then convert to radians

OpenStudy (anonymous):

no other way about it

OpenStudy (anonymous):

in*

OpenStudy (anonymous):

for d) cosxsinx-2cosx = 0 cosx(sinx-2) = 0 solve cosx = 0 and sinx = 2

OpenStudy (anonymous):

thank you! i may ask you to clarify ob it tomorrow

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