Mathematics
15 Online
OpenStudy (anonymous):
Hey! Can someone please help me with
B, C, and D? Thanks a lot! :)
P.S. check the attachment! :P
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OpenStudy (anonymous):
OpenStudy (anonymous):
for b, make the csc into 1/sin
OpenStudy (anonymous):
i did but how would you solve it?
OpenStudy (anonymous):
you will get sin^2(x) = 3/4
OpenStudy (anonymous):
would you leave it like that?
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OpenStudy (anonymous):
nope. square root and use sin inverse
OpenStudy (anonymous):
would i put it into the calculator?
OpenStudy (anonymous):
remember square root gives you 2 solutions, use sin inverse for both
OpenStudy (anonymous):
\[\sin^{-1} (\sqrt{\frac{ 3 }{ 4 }}) and \sin^{-1} (-\sqrt{\frac{ 3 }{ 4 }})\]
OpenStudy (anonymous):
would i put that into the calc?
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
is there a way i could do it w/o the calc?
OpenStudy (anonymous):
it is a special angle. you must memorize it
OpenStudy (anonymous):
the answer is pi/3
OpenStudy (anonymous):
how did you get that?
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OpenStudy (anonymous):
you must memorize the special angles. or you can play around with the calculator and see what you get tin degrees then convert to radians
OpenStudy (anonymous):
no other way about it
OpenStudy (anonymous):
in*
OpenStudy (anonymous):
for d)
cosxsinx-2cosx = 0
cosx(sinx-2) = 0
solve cosx = 0 and sinx = 2
OpenStudy (anonymous):
thank you!
i may ask you to clarify ob it tomorrow