three times the first of three consecutive odd integers is 3 more than twice the third.What is the third integer?

Question

hartnn · Answer

could u form an equation ?

anonymous · Answer

yup

hartnn · Answer

where u stuck ?

mayankdevnani · Answer

SORRY!! for bothering... @hartnn if x is first number, next two are x+2, and x+4 (increase of 2 each time!) so equation becomes 3x = 2(x+4)+3 solving x = 11 so numbers are x 11,13,15 three times first = 33 33 is 3 more than twice the third (2*15) = 30) yes 33 is 3 more than 30! http://answers.yahoo.com/question/index?qid=20110103190852AAqAFL2

anonymous · Answer

3x+x+1+x+3=3+2(x+3)

hartnn · Answer

plz don't copy answers from yahoo.com....

mayankdevnani · Answer

i don't copy them i also mention link...sir

mayankdevnani · Answer

ok    @laraib

anonymous · Answer

@hartnn

anonymous · Answer

@mayankdevnani it says odd integer

hartnn · Answer

wait, how did u get left side ?

mayankdevnani · Answer

yaa it gets 33 which is an odd no.    @laraib

hartnn · Answer

if smallest is x 
then others are 
x+2.,x+4

hartnn · Answer

u took, x+1 and x+3 
thats incorrect

hartnn · Answer

three times the first of three consecutive odd integers -->3x
3 more than twice the third---> 2(x+4) + 3

anonymous · Answer

What if we take (x-2), x and (x+2) ??

hartnn · Answer

will do.

hartnn · Answer

we get same answer.

anonymous · Answer

Isn't it easier one??

anonymous · Answer

3(x-2) = 2(x+2) + 3..

hartnn · Answer

can't say easier....just another method.

hartnn · Answer

both equations are equally easy to solve..

anonymous · Answer

x = 10 + 3