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simplify the equation 2/2+√3
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multiply top and bottom by \[2-\sqrt{3}\] which is called the conjagate
that will remove your radical from the denomonator and make life easier
@evy15 this process is known as rationalization:)
ok. working it out and will post my answer in a bit
\[\frac{ 2 }{2+\sqrt{3} }\times \frac{ 2-\sqrt{3} }{2-\sqrt{3} }\]
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\[\frac{ 2(2-\sqrt{3}) }{( 2+\sqrt{3})(2-\sqrt{3}) } = \frac{ 4-2\sqrt{3} }{ 4-3} = 4-2\sqrt{3}\]
yeah this is what I got, thank u so much
np good luck with the rest of your homework.
thanks
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