Question

How would I put (-144) to the 1/2 power in radical form?

Answer 1

this is #13

Answer 2

1/2 power is square root.

Answer 3

Can you explain to me how you do this step by step?

Answer 4

i^2=-1(-144)^1/2=(12*12 i^2)^1/2=12i

Answer 5

Why is there a variable in the equation?

Answer 6

i=for use -ve

Answer 7

i=imag

Answer 8

I'm sorry but I still don't understand. Can you explain this to me?

Answer 9

your ans

Answer 10

\(\large (-144)^{1/2} = \sqrt{-144}\)

Answer 11

sister your book ans

Answer 12

\(\large \sqrt{-144}=\sqrt{-1} \cdot \sqrt{144}\)

\(\large \sqrt{-1} = i\), \(\large \sqrt{144}=12.\)

Answer 13

oh okay, thank you. can you guys explain to me how to simplify the expression 16^3/4 if possible?

Answer 14

Rational exponents are 'power-over-root'

\(\large 16^{3/4} = \sqrt[4]{(16)^3}\)

Answer 15

16^(3/4)=(2^4)^(\[16^(3/4)=(2^4)^(3/4)=2^((4\times3)/4)=2^3=8

Answer 16

^wow, what a way to over-complicate something that is really simple. :-p

Answer 17

\(\large 16^{3/4}=(\sqrt[4]{16})^3\)

\(\large \sqrt[4]{16} =2\)

\(\large 2^3=8\)

Answer 18

16^1-1/4=16^1/16^1/4=16/2=8

Answer 19

\[(-144)^{\frac{1}{2}}=12 \sqrt{-1}=12 i \]\[-144^{\frac{1}{2}}=-12 \]