Question

i need to find out how many volleyballs will fit in my classroom. what should i do after i find the volume of the classroom and the volume of the volleyball?

Answer 1

volume of class/volume of ball = answer

Answer 2

is there a more accurate answer because that would make me divide out all the small spaces between the volleyballs.

Answer 3

so we are assuming the ball is solid? because I would just cram them in the room:)

Answer 4

so you need the dim of the ball, what is it?

Answer 5

i'm talking about the space in the diamond.

Answer 6

I know... I was joking

Answer 7

the spheres aren't cubes so it doesn't work like that

Answer 8

yes, but you understand a volley ball is not solid and you could cram them in there to fill every inch...But this is not what the question is asking I take it

Answer 9

we need more information then the volume of the room and sphere, we need the deminsions

Answer 10

i just need help on approaching this problem. after i find those two volumes what should i do?

Answer 11

if the circumference is 1 ft then treat each ball like a 1 ft box

Answer 12

fir the third time, I need more information than the volume of the room and spheere. If the room is 1 inch high and 50 miles long you will fit none of the balls in the room...........

Answer 13

so i pretend each ball is a cube and then what?

Answer 14

i don't need an answer. i just want to know how i would do it

Answer 15

This is a question in mathematical "packing", a topic that comes up in physical chemistry. For 2-dimensions, the most efficient packing is a ball with 6 balls around it. Now, to go into the 3rd dimension, you would start placing balls on the top of each tirangle of balls to form a tetrahedron (one of the perfect solids). This is your start conceptually.

Answer 16

huh?

Answer 17

I'll try to draw it.

Answer 18

Terrible drawing I know. Now for each triangle or group of THREE circles, you put a ball on TOP of that like thisThat ball in the center is on TOP.