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can someone help me please? Find the derivative of the function s(x) = square root x + 3/square root x
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\[\sqrt{x} + 3/\sqrt{x}\]
you should memorize the derivative of \(\sqrt{x}\) because it is a very common function the derivative of \(\sqrt{x}\) is \(\frac{1}{2\sqrt{x}}\)
as for \(\frac{3}{\sqrt{x}}\) you can rewrite it as \(3x^{-\frac{1}{2}}\) and use the power rule
\[1/2\sqrt{x} - 3x^-1/2\]
is that correct ?^^^
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no
the first part is right, you still have to take the derivative of \[3x^{-\frac{1}{2}}\] using the power rule
i just rewrote it in exponential form, you still have to find the derivative
so -3/2x-1?
\[\frac{ -3 }{ 2 }x^1\]
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@satellite73
@satellite73 \[\frac{ 1 }{ 2 }\sqrt{x}+ -3/2x ^{-1}\]
is that correct?
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