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please explain?? what are the solutions of 1/2(2x-3)^2+1=11
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1/2(2x-3)^2+1=11 1/2(2x-3)^2+1-1=11-1 1/2(2x-3)^2=10 2*( 1/2(2x-3)^2 )=2*10 (2x-3)^2 = 20 Can you take it from here?
ill try
ok tell me what you get
im stuck
where
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I squared the equation
no, you take the square root of both sides
oh ok
so far I have 2x-3=2√ 5
good
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remember it should be +- (plus/minus) 2√ 5
since there are 2 solutions to any quadratic
im not sure what to do next?
do you add the 3 to the other side
yes
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so is it 2x=3±2√ 5?
good
keep going
so its x=3/2±√5
you can write it like that (\(\Large x = \frac{3}{2}\pm\sqrt{5}\)) or you can write it like \[\Large x = \frac{3\pm2\sqrt{5}}{2}\]
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ok thanks sooo much
yw
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