How do I solve this radical expression?
The expression is
And the choices are:
Expressions are not solved, only simplified.
I don't see any common terms so it's hard to combine them
my bad, i meant simplified haha
Try simplifying the radicals by finding perfect square factors.
like prime numbers?
No, perfect squares are numbers that you can get rational square roots from, like 1, 4, 9, 16, 25, 36, etc.
Check out 48 and 54.. try factoring them.
54 would be 9 and 6 and 48 would be 16 and 3
Right, so remember that the square root of a product is equal to the product of the square roots.. \(\large \sqrt{54}=\sqrt{9}*\sqrt{6}\) \(\large \sqrt{48}=\sqrt{16}*\sqrt{3}\)
3 square root of 6 and 4 square root of 3?
Yep, now you have like terms to add.
which ones?
ohhh i get it
i solved it and got b
No, that can't work. If there were a √9, it would simplify to 3. There are both groups of √3 and groups of √6
my bad, they were sent in a different order than on my paper. it would be C on here
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