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Mathematics 6 Online
OpenStudy (anonymous):

How do I solve this radical expression?

OpenStudy (anonymous):

The expression is

OpenStudy (anonymous):

And the choices are:

OpenStudy (anonymous):

Expressions are not solved, only simplified.

OpenStudy (anonymous):

I don't see any common terms so it's hard to combine them

OpenStudy (anonymous):

my bad, i meant simplified haha

OpenStudy (anonymous):

Try simplifying the radicals by finding perfect square factors.

OpenStudy (anonymous):

like prime numbers?

OpenStudy (anonymous):

No, perfect squares are numbers that you can get rational square roots from, like 1, 4, 9, 16, 25, 36, etc.

OpenStudy (anonymous):

Check out 48 and 54.. try factoring them.

OpenStudy (anonymous):

54 would be 9 and 6 and 48 would be 16 and 3

OpenStudy (anonymous):

Right, so remember that the square root of a product is equal to the product of the square roots.. \(\large \sqrt{54}=\sqrt{9}*\sqrt{6}\) \(\large \sqrt{48}=\sqrt{16}*\sqrt{3}\)

OpenStudy (anonymous):

3 square root of 6 and 4 square root of 3?

OpenStudy (anonymous):

Yep, now you have like terms to add.

OpenStudy (anonymous):

which ones?

OpenStudy (anonymous):

ohhh i get it

OpenStudy (anonymous):

i solved it and got b

OpenStudy (anonymous):

No, that can't work. If there were a √9, it would simplify to 3. There are both groups of √3 and groups of √6

OpenStudy (anonymous):

my bad, they were sent in a different order than on my paper. it would be C on here

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