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27. Write the equation of a line that passes through the points ( -2, 5) and (-2, 11) @MathLegend
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First, we need a slope. y2-y1/x2-x1
Can you @kendoll substitute in the proper values?
11-5/-2-2 ?
11-5/-2+2
6/0?
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Yes.
thts it ?
No.
so wat we do now
Now, we need to use... point slope form... y-y1=m(x-x1) Can you substitute in those values?
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no?
y-5=0(x+2)
Can you solve for y?
y-5=0(x+2) +5 +5
ok so what does y equal?
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y=5(x+2)?
@kendoll y-5=0(x+2) Remember anything multiplied by 0 is 0... y-5 = 0 +5 +5 ---------- y = 5
y= 5 is your final answer. It can not be y=mx+b since a slope of zero is just a horizontal line.
If this were graphed it would look like...
wat about the x+2 it dissapear
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|dw:1353204010655:dw|
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