find the domain and range f(x)=x+1/x-1

Question

tkhunny · Answer

You have written $f(x) = x + \dfrac{1}{x} - 1$.  Is this what you intended?

abb0t · Answer

solve for the denominator, because you know that 1/0 isn't really true. In order to make it true, x must be greater than 1. 

x-1 = 0
x = 1

anonymous · Answer

@tkhunny no $$f(x) = x+1\div x-1$$

anonymous · Answer

@abb0t so what you mean the domain is: all real numbers except "1"? right?

abb0t · Answer

Yes. Correct.

anonymous · Answer

@abb0t if domain is D:{all real numbers\ 1} what is the range?

anonymous · Answer

$$f(x)=\frac{x+1}{x-1}$$ domain all real numbers except $x=1$ where the denominator is zero

anonymous · Answer

and what is the range? @satellite73

anonymous · Answer

range is also going to be all real number except 1, because a fraction is only equal to one if the numerator and denominator are the same, and here they cannot be equal

anonymous · Answer

thanksss

anonymous · Answer

yw

tkhunny · Answer

That's the same thing.  Please make sure you know the difference between:

x+1/x-1

and

(x+1)/(x-1)

Very different animals.

The first is what you wrote.  The second is what you intended.