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Mathematics 18 Online
OpenStudy (anonymous):

Let f be a continuous and bounded function on [a,b] such that if

OpenStudy (anonymous):

OpenStudy (anonymous):

any idea?

OpenStudy (anonymous):

not really,but it kind of looks like a set up for integrating by parts

OpenStudy (anonymous):

I guess so..

OpenStudy (anonymous):

F'(x)=f(x) so we can say F'(t)=f(t) right..

OpenStudy (anonymous):

that is what i was thinking, yes

OpenStudy (anonymous):

maybe not exactly what you want, but you would get something like \(gF-\int f g'\)

OpenStudy (anonymous):

\[\lim_{b \rightarrow} \int\limits_{0}^{b }G(t)F'(t)dt=\]

OpenStudy (anonymous):

I guess enough to show that \[\int\limits f g'\] is convergent

OpenStudy (anonymous):

first part is no problem, since \(\lim_{t\to \infty}g(t)=0\) and \(\int_a^\infty f(t)\) is bounded

OpenStudy (anonymous):

yeah you hit the nail on the head, and frankly i don't see why that is true, so this might be the wrong approach

OpenStudy (anonymous):

because all you know about \(g'\) is that \(g'\leq 0\)

OpenStudy (anonymous):

does this come in a section after some theorem or lemma that maybe you are supposed to use?

OpenStudy (anonymous):

no, this is homework, but prof gave the hint and said that you should use integration by part..

OpenStudy (anonymous):

well then i guess this is the right approach!

OpenStudy (anonymous):

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