Question

The horizontal range, R, in feet that a baseball travels is modeled by this formula. The initial velocity, v, is 90 feet per second. The ball is pitched at an angle of θ degrees with the horizontal. When θ = 26º the ball travels 200 feet. At what other value of θ witll the ball travel 200 feet? (Enter only the number.)

Answer 1

Check out this page

http://hyperphysics.phy-astr.gsu.edu/hbase/traj.html

and scroll to the section "Angle of Launch"

Answer 2

ok thansk

Answer 3

np

Answer 4

how do i use it because i put 200 in then i put all these numbers in?

Answer 5

gR/v^2

9.8*200/(27.432^2) ... Note: 90 ft/s = 27.432 m/s

2.6046

but there's a problem, this should be in the range [-1, 1]

Answer 6

so it seems like something is off

Answer 7

ohh something off with the website ? u told me to use?

Answer 8

no, it looks correct

something seems off with the numbers given

Answer 9

oh wait, I'm using the wrong numbers, hold on

Answer 10

hhaha well if there is then im out luck becuase they way i wrote it is the way it givn on my paper???

Answer 11

(1/2)*arcsin(gR/v^2)

(1/2)*arcsin(32*200/90^2)

(1/2)*arcsin(0.790123)

(1/2)*52.1970075 or (1/2)*(180 - 52.1970075)

26.09850375 or 63.90149625

Answer 12

So the other theta value is roughly 63.90149625 degrees

Answer 13

Thank u sooo much dude :)