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assuming an angle in quadrant I , evaluate csc(cot^-1 4/3) a) 4/5 b)5/4 c)5/3 d)3/5
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@ajprincess could you please please help me!?
They want \[ \csc(\cot^{-1}(4/3)) \]?
Remember that \(\cot(\alpha)=\cos(\alpha)/\sin(\alpha)\)
yes thats what they're asking
how will that identity help?
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Because this: |dw:1353223498435:dw|
ok
We can see that 4 corresponds to sin, and 3 corresponds to cos.
|dw:1353223616437:dw|
So first you need to find the hypotenuse.
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Remember that cos is adjacent over hypotenuse. csc is just the reciprocal of cos, ie hypotenuse over adjacent. We just need the hypotenuse.
5
@wio
is it 5/3 @wio ?
Yes.
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cot^-1=4/3 tan x=4/3 hypotnuse5 sinx=4/5 cosec=5/4
so its 5/4?
yes
hope it helps
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