Question

Sulfur vapor is analyzed by photoelectron spectroscopy (PES). Measurements determine that photoelectrons associated with the 1st ionization energy of sulfur move with de Broglie wavelength λ=3.091 A˚. What is the maximum wavelength (in meters) of radiation capable of ionizing sulfur and producing this effect?

Answer 1

did you get an answer?

Answer 2

Can't get it either

Answer 3

i got the ans...
they hv given the debrogli wavelength
so....velocity is 2.353*10^6m/s using lambda=h/mv
and E=25.21*10^-19J using E=1/2mv2
thn h*nu=K.E+B.E
here B.E=I.E of s in J
wch is 10.36eV*1.602*10^-19
=16.5967*10^-19
nw using eq h*nu=K.E+B.E
i gt lambda..
=47.4*10^-9