What is the solution to the rational equation (3)/(2)-(1)/(x-5)=(-2)/(2x-10)? Can someone please help me!
You can cross multiply to get your answer. Don't forget to check the answers you get to make sure that your answers work and aren't extraneous (A solution of a simplified version of an equation that does not satisfy the original equation.) http://www.mathwords.com/e/extraneous_solution.htm
okay @wonder291
but what exactly do i do to the other side of the equation
\[\frac{ 3 }{ 2 }-\frac{ 1 }{ x-5 }=\frac{ -2 }{ 2x-10 }\] You could multiple the entire equation by the least common multiple of all the denominators... Then you could combine like terms
could you guide me through the problem im struggling on this a lot.
The Least Common Multiple (LCM) is basically the smallest (non-zero) number that is a multiple of two or more numbers. http://www.mathsisfun.com/least-common-multiple.html The same works for expressions with variables. For example, in this problem the numbers we have (to find the LCM of) are 2, x-5, and 2x-10.
okayy
Do you still need help with anything?
Yes i am really trying my hardest to solve this problem but i just get confused on it .
What step are you on now?
cross multiplying
Let me show you an example with other numbers \[\frac{ 2 }{ 3 }=\frac{ 4 }{ 6 }\] Cross multiplying in this example means you multiple one numerator by the other denominator. |dw:1353282497570:dw| 2*6=3*4 12=12 The same would work with these expressions with variables.
this is what i got 3x-15-1=(-2)/(2x-10)
\[\frac{ 3 }{ 2 }-\frac{ 1 }{ x-5 }=\frac{ -2 }{ 2x-10 }\] What did you get for the least common multiple?
i Really dont know :(
It's ok, I'll help you... To find the least common multiple (denominator because they're a fraction) for the following, 2, x-5, and 2x-10. Try multiplying factors together so that you only have 1 factor. Try not to multiply all of them at once; try two at a time.
okay i did it but it did not work
another way to find it is to see if some factors divide into other factors
for example, for 5, 2x+1, 10x+5 10x+5 is divisible by 5; and it is divisible by 2x+1; therefore it is the least common multiple
It will work for 2, x-5, and 2x-10.
for the example, 10x+5 is the least common multiple
okay i multiplied them all by the lcm what do i do next
You can combine like terms. for example: 2x+1+5x 2x and 5x are like terms. so you end up with 7x+1
but before that, make sure you multiply everything out
okay is the answer X=5
substitute the answer you get back into the equation (to check), and remember that the denominator can never equal 0!
i Believe this is right x=5
If none of your solutions work, then there is no solution to the equation! (sometimes this happens)
Oh so its no solution because it was'nt quite working
\[\frac{ 3 }{ 2 }-\frac{ 1 }{ x-5 }=\frac{ -2 }{ 2x-10 }\] Yes, just for this rational equation.
thankyou soo much for the guidance
No problem! :)
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