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What is this simplified?
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\[\frac{ x+1 }{ x^2+x-6}\div \frac{ x^2+5x+4 }{ x+4 }\]
when you divide by a fraction its the same as multiplying by its reciprocal
stay, change , flip?
you will want to do that first after that, factor the two quadratic equations
flip the second fraction and change the divide sign to a multiply sign
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\[\frac{ x+4 }{(x+1)(x+4) }\]
yes now... \[\frac{ x+1 }{x ^{2}+x+6 }*\frac{ x+4 }{ (x+1)(x+4) }\]
factor the denominator of the first fraction too
how would i do that one?
actually you don't have to! :P now you can cancel out some terms see the x+1? and the x+4?
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yes
would the denominator be (x+3)(x+4) ?
@shravanm1
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