Write the equation of the line that satisfies the given conditions. Express the final equation in standard form. Contains the point (-2, 4) and is perpendicular to the line 3x − y = 4
i hope you don't mind that i solve this in slope intercept form instead.
I don't mind. as long as I can properly convert it to standard
3x-y=4, rearrange to get y=3x-4, the slope for this equation is 3. since the wanted equation is perpendicular to this eqation, its slope will be -1/3. plug in (-2,4) in y=mx+b 4=-(1/3)(-2)+b and solve for b
You put it in standard form?
yes, after you've figured out what the slope and the intercept are
ok
I got 4= 2/3b which reduced is b=2/3
4=(2/3)+b isolate b b is not equal to 2/3
oh..
yes...
b= 10/3 ?
no 4=(2/3)+b what do you need to do to isolate b?
subtract the 2/3
so -2/3 + 4 = b
sorry, you were right it is 10/3, I wasn't thinking when i saw that you had written 4= 2/3b where b=2/3
Its ok.. So with 10/3, where do I go now to solve the problem?
plug that the slope into the standard form equation
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