Question

Find f'(x) for f(x)=(x-4)/sqrt(2x-3)

Answer 1

Do u know how to use the power rule? it allows you to calculate the derivative of f(x)

Answer 2

i used chain rule for the bottom.

Answer 3

so do you know the quotient rule.
i assume its: \[\frac{x-4}{\sqrt{2x-3}}\]

Answer 4

You can use the product rule as well by re-writing it as:
\[(x-4)* \frac{1}{\sqrt{2x-3}} => (x-4)* \frac{1}{(2x-3)^{1/2}} => (x-4)(2x-3)^{-1/2}\]

Answer 5

Btw, this is not differential equations :)

Answer 6

i'd rather use quotient rule...

Answer 7

oh sorry haha.

Answer 8

so where are you stuck with the quotient rule

Answer 9

anyhow, the quotient rule is easier for this :)

Answer 10

i mean product rule** lol

Answer 11

the combining them all together part...i used chain rule for the derivative of the bottom, and i got (-1/2(2x-3)^-3/2 + 2)

Answer 12

times the top, so ((x-4)(-1/2(2x-3)^-3/2 + 2)-x+4)/2x-3

Answer 13

That's after quotient rule and chain rule^

Answer 14

so where are you stuck after it

Answer 15

just the combining part. combining x-4 with the entire equation lol.

Answer 16

can you use the drawing tool? or latex?

I don't seem to decipher what you wrote..

Answer 17

\[((x-4)(\frac{ 1 }{ 2 }(2x-3)^{\frac{ -3 }{ 2 }} +2)-x+4)/x-4\]

Answer 18

It's the entire thing over x-4

Answer 19

@Omniscience