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Mathematics 19 Online
OpenStudy (anonymous):

What is the limit as x approaches infinity of x^1/x

OpenStudy (anonymous):

start with \[x^{\frac{1}{x}}=e^{\frac{1}{x}\ln(x)}\] so your job is to find \[\lim_{x\to \infty}\frac{\ln(x)}{x}\] then raise \(e\) to that number

OpenStudy (anonymous):

if you plug that equation into a graphing calculator you can then see the end behavior and then write the limit i hope this helps. :)

OpenStudy (anonymous):

\[\lim_{x\to \infty}\frac{\ln(x)}{x}=0\] pretty much from your eyeyballs then you get \(e^0=1\)

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