Question

Coefficient must be squared using the original x term and added to both sides of the equation
4x² - 8x = 52 solve

Answer 1

Step 1:
Put all ur terms on the same side. Therefore move 52 to the left side of the equation. what do you get when you do this?

Answer 2

I would then add the 52 on the left side?
Am I doing the opposite?

Answer 3

Please explain... need your help.

Answer 4

I am just walking you thru the steps. Can u do step 1?

Answer 5

Yes.

Answer 6

what do u get?

Answer 7

If I move it to the left I get 52+4X2-8x=52

Answer 8

or wait.... now I don't have terms on the right yet... ugh!

Answer 9

when I say term on the right I mean the term that is to the right of the equal sign (52)

Answer 10

Subtract 52 on both sides to move the 52 from the right of the equal (=) sign to the left side of the (=) sign.
Step1:
4x^2-8x=52
-52 -52
You should get: 4x^2-8x-52=0

Answer 11

Do u understand this?

Answer 12

I need you to explain why?

Answer 13

We are trying to solve for 'x'
In order to do that, we need to move the 52 to the left hand side

Answer 14

ok

Answer 15

Is there a common factor between the coefficients (or numbers) in the quadratic equation?

Answer 16

huh? The gcm?

Answer 17

2

Answer 18

I'm dumb at this stuff

Answer 19

Close nope its 4. So take 4 outside a parentheses:
4(x^2-2x-13)=0

Answer 20

Divide both sides by 4:
4/4(x^2-2x-13) = 0/4
Get: x^2-2x-13 = 0
next step is to factor: by factoring or use the quadratic formula.

Answer 21

Do u know the quadratic formula and how to use it to solve a quadratic equation?

Answer 22

Quadratic formula:
\[x=-b \pm \frac{ \sqrt{b^{2}-4ac} }{ 2a }\]

Answer 23

Correct equation:
\[x=\frac{ -b \pm \sqrt{b^{2}-4ac} }{ 2a }\]
a=1, b= -2, c=-13
\[x=\frac{-(-2)\sqrt{(-2)^{2}-4(1)(-13)} }{ 2(1) }\]

Answer 24

Do you understand how i got this?
1x^2-2x-13=0,
a=1, b=-2, c=-13, note got it from the numbers without the x-variable

Answer 25

r u there? @asrodgers