Question

LOG

Answer 1

\[\log_{3x+7}(5x+3)+\log_{5x+3}(3x+7)=2 \]

Answer 2

Do you know the log rules?

Answer 3

some of them

Answer 4

which one do I need

Answer 5

Do you know the change of base rule? The multiplication/division rules?

Answer 6

yesssss

Answer 7

Use the change of base rule to a common base such as e, for BOTH of the logs.
Then you will find you can cancel out the fractions

Answer 8

I don't see how they cancel

Answer 9

Oh I thought you were supposed to prove it

Answer 10

no solve

Answer 11

Find a value of x that makes 5x+3 = 3x+7. Then, you get 1+1=2.

Answer 12

Because \(\log_{b}b = 1\)

Answer 13

@ArkGoLucky, does that make sense?

Answer 14

That makes sense but I don't know how to do that

Answer 15

Do you mean you can't solve for x? Or that you can't see why we need to do that.

Answer 16

nevermind I understand. thanks

Answer 17

Okay, great!