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Mathematics 14 Online
OpenStudy (anonymous):

(cos(x) - √(2)/2 ) (sec(x) -1) = 0 Part 1. Use the zero product property to set up and solve two equations involving cosine that will lead to solutions to the original equation. (cos(x) - √(2)/2 )=0 (sec(x) -1)=0 Is this right? Part 2. Use a reciprocal identity to express the equation involving secant in terms of sine, cosine, or tangent. Part 3. Solve each of the two equations in Part 1 for x, giving all solutions to the equation.

OpenStudy (anonymous):

yes that is right, which part do you need help with?

OpenStudy (anonymous):

2

OpenStudy (anonymous):

it just means to change secx secx = 1/cosx

OpenStudy (anonymous):

so just ((1/cosx)-1)=0?

OpenStudy (anonymous):

is that correct?

OpenStudy (anonymous):

yes but simplify it

OpenStudy (anonymous):

1/cosx=1

OpenStudy (anonymous):

Take the reciprocal, cosx = 1

OpenStudy (anonymous):

cosx=\[\sqrt{2}/2\] and 1

OpenStudy (anonymous):

yup now take the inverse of both sides Therefore find x

OpenStudy (anonymous):

\[x=\pm \pi/4 + 2n\pi \]

OpenStudy (anonymous):

is that correct?

OpenStudy (anonymous):

hmmm

OpenStudy (anonymous):

2pi(n) ?

OpenStudy (anonymous):

x = 2pi(n), 2pi(n) +- pi/4 n E Z

OpenStudy (anonymous):

what is nEZ?

OpenStudy (anonymous):

Dont ever forget the n E Z

OpenStudy (anonymous):

It means where n is a member of the set Z (integers), meaning that n is an integer

OpenStudy (anonymous):

ok, thanks so much

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