(cos(x) - √(2)/2 ) (sec(x) -1) = 0
Part 1. Use the zero product property to set up and solve two equations involving cosine that will lead to solutions to the original equation.
(cos(x) - √(2)/2 )=0
(sec(x) -1)=0
Is this right?
Part 2. Use a reciprocal identity to express the equation involving secant in terms of sine, cosine, or tangent.
Part 3. Solve each of the two equations in Part 1 for x, giving all solutions to the equation.
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OpenStudy (anonymous):
yes that is right, which part do you need help with?
OpenStudy (anonymous):
2
OpenStudy (anonymous):
it just means to change secx
secx = 1/cosx
OpenStudy (anonymous):
so just ((1/cosx)-1)=0?
OpenStudy (anonymous):
is that correct?
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OpenStudy (anonymous):
yes but simplify it
OpenStudy (anonymous):
1/cosx=1
OpenStudy (anonymous):
Take the reciprocal, cosx = 1
OpenStudy (anonymous):
cosx=\[\sqrt{2}/2\] and 1
OpenStudy (anonymous):
yup now take the inverse of both sides
Therefore find x
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OpenStudy (anonymous):
\[x=\pm \pi/4 + 2n\pi \]
OpenStudy (anonymous):
is that correct?
OpenStudy (anonymous):
hmmm
OpenStudy (anonymous):
2pi(n) ?
OpenStudy (anonymous):
x = 2pi(n), 2pi(n) +- pi/4 n E Z
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OpenStudy (anonymous):
what is nEZ?
OpenStudy (anonymous):
Dont ever forget the n E Z
OpenStudy (anonymous):
It means where n is a member of the set Z (integers), meaning that n is an integer