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Plane A which contains an isosceles right triangle forms a dihedral angle of 60 degrees with another plane B. if the hypotenuse of the triangle lies in plane B and measures 8 in., find the distance from the vertex of the right angle to plane B, and the length of the projection of each leg of the triangle on plane B.
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So, it's |dw:1353327509163:dw| and |dw:1353327558921:dw| Now, first we'll need to find the length of the hypotenuse and vertex of right angle. That's done by using the tan 45. Now, we'll find the distance from the vertex of the right angle to plane B. Since we have the length, which will be \(4 \tan 45^o\), we'll apply the sine to find that length. It will be |dw:1353327784152:dw| i.e. (4 tan 45)(sin 60)
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