Question

Simplify: (h2)5 (1 point)

(0 pts) h7 I thought it was this one
(0 pts) h5
(0 pts) h2
(1 pt) h10 It was this one obviously c:


Can someone explain how I should of gotten h10?

Answer 1

\[(h^2)^5 \] Is this it?

Answer 2

The problem yesh c:

Answer 3

Well let's say we have \[(x)^3\]

we can rewrite it as \[(x)*(x)*(x)\]
right?

Answer 4

Apply that same thing to this problem.

Answer 5

\[(h^2)^5= (h^2)*(h^2)*(h^2)*(h^2)*(h^2) \]

Answer 6

Which can further be simplified to\[(h^2)*(h^2)*(h^2)*(h^2)*(h^2)= h*h*h*h*h*h*h*h*h*h=h^{10}\]

Answer 7

See it?

Answer 8

*Facepalm*

Answer 9

I do see it now haha thanks

Answer 10

All that means is that if you have the exponent of a variable that already has an exponent all you do is multiply the exponents

Answer 11

In this case you had 2 and 5

Answer 12

which makes 10

Answer 13

I was thinking okay well if I lay out 2 h's then 5 h's I would have 7 but when you take h^2 It's not just one H like I was thinking for whatever reason XD

Answer 14

bruh ur pic is lowkey scary asf