Evaluate the integral by making the given substitution. the integral of cos^6 θ sin θ dθ, u = cos θ
So with a substitution, we want to replace ALL of the Theta's and D(Theta) with U's and du. Let \[\large u=\cos \theta\]Taking the derivative gives us,\[\large du=-\sin \theta d \theta\] But our equation includes a sin theta, without the negative, so let's move the negative to the other side of that equation. \[\large -du= \sin \theta d \theta\]
So now we can replace the cos theta with something involving u, and we can replace the sin theta d(theta) with something involving du, and it should simplify our integral.
\[\large \int\limits\limits (\cos \theta)^6 (\sin \theta d \theta) \rightarrow \quad \int\limits\limits (u)^6(-du)\]
Understand what we did there? :D Substitutions can be a little tricky to get used to. It's not as easy as differentiation was ^^
ohh okay i see what i did wrong now. thank you!
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