Evaluate the definite integral from x=0 to x=1
the cubed root of (1 + 7x) dx

Question

Evaluate the definite integral from x=0 to x=1
the cubed root of (1 + 7x) dx

anonymous · Answer

A substitution step would simplify the problem:
$$\int\limits_{0}^{1}(1+7x)^{\frac{1}{3}}dx$$
$$u = 1+7x$$
$$\frac{du}{dx} = 7 $$
$$dx = \frac{du}{7}$$

$$\frac{1}{7}\int\limits_{}^{}u^{\frac{1}{3}}du$$

anonymous · Answer

you'll have to redo the bounds of integration (ie it was 0-1 when the integral was in terms of 'x', but now the integral is in terms of 'u')

anonymous · Answer

ohhh that was why i messed up. thank you!

anonymous · Answer

you got the new bounds?

anonymous · Answer

yea i thought so, but my answer was wrong. it's okay though. it's only one point off my homework. thanks anyway!