Question

limit as x approaches 0 of:
(tan(x)-sin(x))/sin^3(x)
I've only thought of simplyfying it to this form:
(1-cos(x))/(cos(x)*sin^2(x))

Answer 1

\[\frac{ 1-\cos x }{ \cos x * \sin^2x }\]

Answer 2

Well, I got to
\[\frac{ \cos x - 1 }{ \sin^2 x } + \frac{ 1 }{ \cos x }\]

Answer 3

I've done it :)
\[\frac{\cos x−1}{\sin^2x}+\frac{1}{\cos x}=\]
\[= \frac{1}{\cos x+1} +\frac{1}{\cos x} \]

Answer 4

I mean
\[-\frac{ 1 }{ \cos x + 1 } + \frac{1}{\cos x}\]