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Mathematics 20 Online
OpenStudy (anonymous):

Find the exact location of all the relative and absolute extrema of the function f(x) = 13xe^ 1-x(squared)

OpenStudy (anonymous):

\[13xe ^{1-x^2}\]

OpenStudy (anonymous):

Take the derivative. Then set it equal to 0

OpenStudy (anonymous):

i dont know how to take the deriviatve of that equation

OpenStudy (anonymous):

Also, make sure you include the domain points.

OpenStudy (anonymous):

i need help finding the derivative of this equation though

OpenStudy (anonymous):

The derivative would be -13e^(1-x^2)(2x^2-1)

OpenStudy (anonymous):

Btw, the max is at 1/sqrt2, and the min is at -1/sqrt2

OpenStudy (anonymous):

That would be the x value.

OpenStudy (anonymous):

so, max:|dw:1353369319667:dw|

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