Question

determine the equation of the line tangent to the graph of y=15e^(6x^2)-6x
at x=2 in the form y=mx+b

i got m=2160e^144
b=-4305e^144-12

but those are wrong

Answer 1

find the first derivative and then put x=2 you will get the slop at x=2
\[y \prime = 15 e ^{6x ^{2}}\left( 12x \right) - 6\]
now put x=2

Answer 2

15e^(144)(24)-6?

Answer 3

or would it be 15e^(24)(24)-6

Answer 4

first yu have x = 2, now sub 2 where ever x is in the original equation and that gives you the y value.

Answer 5

second, take the first derivative of the original function
then sub x = 2, which is gonna give you the m
:)
and then yu can plug in y-y1=m(x-x1)
and that's it :)

Answer 6

so is my answer i found above that i put in the question completely wrong?

Answer 7

i'll check

Answer 8

thanks

Answer 9

wait actually i think y should equal 15e^(144)-12

Answer 10

no,
it wud be y = 15e^(24) - 12

Answer 11

oo i multiplied the order wrong

Answer 12

what m=?

Answer 13

did u get this for the derivative?